how many sheet metals does it take to stop a 50 BMG ?

Published on January 8, 2017
Duration: 2:10

This video tests the penetration capabilities of a .50 BMG API round against 18-gauge sheet metal. It was determined that 16 sheets of this metal were required to stop the projectile. The experiment utilized a Serbu BFG-50A rifle and highlighted the significant power of the .50 BMG caliber.

Quick Summary

It took 16 sheets of 18-gauge sheet metal to stop a .50 BMG Armor Piercing Incendiary (API) round fired from a Serbu BFG-50A rifle. The test involved lining up 22 sheets, with 6 remaining intact after the shot.

Chapters

  1. 00:00Experiment Setup: 22 Sheets of 18-Gauge Metal
  2. 00:22Firearm & Ammo: Serbu BFG-50A with .50 BMG API
  3. 00:38The .50 BMG Shot
  4. 00:41Results Analysis: Penetration Depth
  5. 01:41Conclusion: 16 Sheets Stop the Round

Frequently Asked Questions

How many sheets of 18-gauge metal did it take to stop a .50 BMG round?

In the experiment conducted by Edwin Sarkissian, it took 16 sheets of 18-gauge sheet metal to successfully stop a .50 BMG Armor Piercing Incendiary (API) round fired from a Serbu BFG-50A rifle.

What type of .50 caliber ammunition was used in the test?

The ammunition used in this penetration test was .50 caliber Armor Piercing Incendiary (API). This type of round is designed for significant penetration and incendiary effects.

What rifle was used to fire the .50 BMG round?

The rifle used for this ballistics test was a Serbu BFG-50A. This is a semi-automatic rifle specifically designed to chamber and fire the powerful .50 BMG cartridge.

What was the setup for the sheet metal penetration test?

The test involved lining up 22 pieces of 18-gauge sheet metal on a stand. A .50 BMG API round was fired into the line of plates to determine how many it would penetrate.

Related News

All News →

More Reviews Videos You Might Like

More from Edwin Sarkissian

View all →